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administrator's blog(LINKS) C, C++ Tutorials, FAQs, and Helpful Articles.(LINKS) C, C++ Tutorials, FAQs, and Helpful Articles.
(FAQ) FREQUENTLY ASKED PROGRAMS IN C, C++FREQUENTLY ASKED PROGRAMS(FAQs) IN C, C++
(Puzzles) Interesting C Programing ProblemsInteresting C Programing Problems (Level- Intermediate to Advance) The following C program segfaults of IA-64, but works fine on IA-32. 1 int main()
2 {
3 int* p;
4 p = (int*)malloc(sizeof(int));
5 *p = 10;
6 return 0;
7 }
Why does it happen so?
The expected output of the following C program is to print the elements in the array. But when actually run, it doesn't do so. 1 #include<stdio.h>
2
3 #define TOTAL_ELEMENTS (sizeof(array) / sizeof(array[0]))
4 int array[] = {23,34,12,17,204,99,16};
5
6 int main()
7 {
8 int d;
9
10 for(d=-1;d <= (TOTAL_ELEMENTS-2);d++)
11 printf("%d\n",array[d+1]);
12
13 return 0;
14 }
Find out what's going wrong.
The following program doesn't "seem" to print "hello-out". (Try executing it) 1 #include <stdio.h>
2 #include <unistd.h>
3 int main()
4 {
5 while(1)
6 {
7 fprintf(stdout,"hello-out");
8 fprintf(stderr,"hello-err");
9 sleep(1);
10 }
11 return 0;
12 }
What could be the reason?
1 #include <stdio.h>
2 #define f(a,b) a##b
3 #define g(a) #a
4 #define h(a) g(a)
5
6 int main()
7 {
8 printf("%s\n",h(f(1,2)));
9 printf("%s\n",g(f(1,2)));
10 return 0;
11 }
Just by looking at the program one "might" expect the output to be, the
same for both the printf statements.
But on running the program you get it as:
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(QUESTIONS) ANSWER THIS:: C, C++ QuestionsANSWER THIS:: C,C++ Questions 1)Which is faster and why 2)how can we include other than a .h using #include 3)which is faster and why fun(typedef struct a X) or fun(typedef struct a *pX) 4)how can we print "HELLO WORLD" with out using semicolon 5) what is the purpose of volatile modeifier 6) how can we avoid multiple enteries of files included by #include 6)why is enum is better compared to #define constant
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